18x^2-16x-4=-2x^2

Solution for 18x^2-16x-4=-2x^2 equation:

18x^2-16x-4=-2x^2

We move all terms to the left:

18x^2-16x-4-(-2x^2)=0

We get rid of parentheses

18x^2+2x^2-16x-4=0

We add all the numbers together, and all the variables

20x^2-16x-4=0

a = 20; b = -16; c = -4;
Δ = b2-4ac
Δ = -162-4·20·(-4)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-24}{2*20}=\frac{-8}{40}
=-1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+24}{2*20}=\frac{40}{40}
=1
$